JEE Main
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- JEE Main
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- Physics
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- Kinetic Theory of Gases
JEE Main · Physics · Kinetic Theory of Gases
If the average translational kinetic energy of a molecule in a gas...
If the average translational kinetic energy of a molecule in a gas is equal to the kinetic energy of an electron accelerating from rest through , then the temperature of the gas molecule is \left(\text { Boltzmann constant }=\times\mathrm{JK}^{-1}\right)
Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
According to question, the translation of a molecule of gas
According to the question, \begin{aligned}& \frac{3}{2}k t=e V \Rightarrow \frac{3}{2}k t=10 e \\
& \begin{aligned}
\Rightarrow \quadT & =\frac{20 e}{3 K_B}=\frac{20 \times 1.6 \times 10^{-19}}{3 \times 1.38 \times 10^{-23}}\\
& =77.3 \times10^3 \mathrm{~K}
\end{aligned}
\end{aligned}$