99 Percentile Qs Bank for JEE MainPhysicsKinetic Theory of Gases
The temperature of an ideal gas is increased from 100 K to 400 K . If the r m s speed of the gas molecule is V at 100 K , then at 400 K it becomes
Options
- A2 V
- B4 V
- C0.5 V
- DV
Correct answer
A. 2 V
Step-by-step solution
∵ r m s speed of molecule V r m s ∝ T for T = 100 K V r m s 1 ∝ 100 For T = 400 K V r m s 2 ∝ 400 therefore, V r m s 1 V r m s 2 = 100 400 or V V r m s 2 = 1 2 or V r m s 2 = 2 V