A mixture of two gases is contained in a vessel. The Gas 1 is monoatomic and gas 2 is diatomic and the ratio of their molecular masses (M1)/(M2) = (1)/(4) . The ratio of root mean square speeds of the molecules of two

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Correct answer: A. 2

From kinetic theory of gases P = (1)/(3)(M)/(V) × V _ rms ^ 2 Since, P and V are constant (same) ∴ M _ 1 V _ rms1 ^ 2 = M _ 2 V _ rms2 ^ 2 ⇒ V _ rms1 ^ 2 V _ rms2 ^ 2 = (M2)/(M1) ⇒ (Vrms1)/(Vrms2) = (M2)/(M1) = 4 / 1 = 2 [ given, (M1)/(M2) = (1)/(4)]

A mixture of two gases is contained in a vessel. The Gas 1 is...

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