Two touching blocks 1 and 2 are placed on an inclined plane forming an angle 60^ with the horizontal. The masses are m₁ and m₂ and the coefficient of friction between the inclined plane and the two blocks are 1.5 and 1.0 , respectively. The force of reaction between the blocks during the motion is ( g= acceleration due to gravity)

Step-by-step solution

According to the question, there are two blocks of masses m₁ and m₂ which are kept in contact on inclined plane of inclination 60^ as shown in the figure, Coefficient of friction between the surface of plane and surface of first block, ₁=1.5 Coefficient of friction between the surface of plane and surface of second block, ₂=1 Now, free body diagram for the first block, If a be the common acceleration, then aligned & m₁ g 60^ - ₁ R₁+R=m₁ a & m₁ g 3 2 -1.5 m₁ g 60^ +R=m₁ a & m₁ g 3 2 - 1.5 m₁ g 2 +R=m₁ a aligned Simi