99 Percentile Qs Bank for JEE MainPhysicsLaws of Motion
The upper half of an inclined plane of inclination θ is perfectly smooth while the lower half is rough. A body released from rest from the top comes to rest at the bottom if the coefficient of friction for the lower half is given by:-
Options
- Aμ = 2 sin θ
- Bμ = cot θ
- Cμ = 2 cos θ
- Dμ = 2 tan θ
Correct answer
D. μ = 2 tan θ
Step-by-step solution
For upper half v 2 = v 2 + 2 a l / 2 = 2 ( g sin θ ) 1 / 2 = g l sin θ For lower half 0 = v 2 + 2 g ( sin θ - μ cos θ ) 1 2 ⇒ - g l sin θ = g l ( sin θ - μ cos θ ) ⇒ μ cos θ = 2 sin θ ⇒ μ = 2 tan θ