Two blocks of masses 3   kg and 2   kg are placed side by side on an incline as shown in figure. A force F = 20   N is acting on 2   kg block along the incline. The coefficient of friction between the block and the incline is same and equal to 0 . 1 . Find the normal contact force exerted by 2   kg block on 3   kg block.

Step-by-step solution

According to question a F force act on the block Now F.B.D. for block 3   kg Where, N is normal provided by 2   kg block f is force of friction μ if coefficient of friction According to newton's second law ∑ F = m a Applied in the direction of incline   3 g   sin   θ + N - f = 3 a   f = μ N 1 Here N 1 is normal force applied by the incline on 2 Kg block   3 g   sin   θ + N - 3 μ g   cos   θ = 3 a