99 Percentile Qs Bank for JEE MainPhysicsLaws of Motion
Find the accelerations of rod A and wedge B in the arrangement shown in diagram. If the ratio of the mass of the wedge to that of the rod equals η, and the friction between all contact surfaces is negligible.
Options
- Ag tan η - α cot α
- Bg tan α + η cot α
- Cg tan α - η cot α
- Dg tan η + α cot α
Correct answer
B. g tan α + η cot α
Step-by-step solution
Step I : Draw force diagram separately. w=acceleration m A g - N A cos α = m A w A .....(i) N A sin α = m B w B-....................(ii) tan α = w A w B ......(iii) According to problem, m B m A = η ......(iv) After solving equation (i), (ii), (iii) and (iv), we get w A = g 1 + η cot 2 α w B = g tan α + η cot α