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99 Percentile Qs Bank for JEE MainPhysicsLaws of Motion

Consider a system of blocks X, A and B as shown in the figure. The blocks A and B have equal mass and are connected by a massless string through a massless pulley. The coefficient of friction between block A and X or B and X is 0.5 . If block X moves on the horizontal frictionless surface what should be Its minimum acceleration such that blocks A and B remain stationary. (g= acceleration due to gravity.)

Options

  1. Ag 3
  2. B3 g
  3. Cg 4
  4. D3 g 4

Correct answer

A. g 3

Step-by-step solution

Given, Mass of block A and B, m_A=m_B=m . Coefficient of friction between each block and surface =0.5 . Block X moves with acceleration a such that block A and B remains stationary. Block B is stationary only when, Tension force on block B is equal to friction force on B . i.e., aligned & T= R & T= m a ... (i) [ R=m a] aligned (i) [ R=m a] Block A is stationary only when friction force on block A is equal to the sum of tension force on block A and applied force on block A . aligned R & =T+m a m g & = m a+m a aligne

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