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A magnet freely suspended in a vibration magnetometer makes 40 oscillations per minute at place A and 20 oscillations per minute at a place B . If the horizontal component of earth's magnetic field at A is 36 10⁻⁶ ~T , then its value at B is

Options

  1. A30 10⁻⁶ ~T
  2. B9 10⁻⁶ ~T
  3. C144 10⁻⁶ ~T
  4. D288 10⁻⁶ ~T

Correct answer

B. 9 10⁻⁶ ~T

Step-by-step solution

Time period of magnet, T=2 I M H In both the condition magnet is same. So, aligned T & 1 H T_A T_s & = H_n H_A aligned gathered 60 / 40 60 / 20 = H_n 36 10⁻⁴ 1 2 = H_n 36 10⁻⁶ gathered Squaring both sides 1 4 = H_n 36 10⁻⁶ H_n=9 10⁻⁴ ~T

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