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A magnet of length 10 ~cm and magnetic moment 1 Am ^2 is placed along side A B of an equilateral triangle A B C . If the length of the side A B is 10 ~cm . The magnetic induction at the point C is ( ₀=4 10⁻⁷ Hm ⁻¹ )

Options

  1. A10⁻⁹ ~T
  2. B10⁻⁷ ~T
  3. C10⁻⁵ ~T
  4. D10⁻⁴ ~T

Correct answer

D. 10⁻⁴ ~T

Step-by-step solution

l=10 ~cm , M=1 Am ^2 Magnetic induction at point ⁺ C (In equatorial position), aligned B & = _a 4 M (C O)^2 =10⁻⁷ 1 ( 10^2-5^2 )^3 & = 10⁻⁷ 1 ( 75 )^3 = 10⁻⁷ (5 3 10⁻² )^3 & = 10⁻⁷ 125 3 3 10⁻⁶ = 10⁻¹ 375 1.732 & =0.000154=1.54 10⁻⁴ ~T & =10⁻⁴ ~T aligned

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