A paramagnetic material shows a net magnetization of 8 A m ^ -1 when placed in an external magnetic field of intensity 0.6 T at a temperature of 4K . When the same material is placed in an external magnetic field of

Correct answer: B. (2)/(3)Am^ - 1 According to Curie's law, Magnetization, I ∝ (MagneticInduction ( B ))/(Absolutetemperature ( T )) ⇒ (I2)/(I1) = B _ 2 T _ 1 B _ 1 T _ 2 ⇒ (I2)/(8) = (0 . 2 × 4)/(0 . 6 × 16) ⇒ I _ 2 = (2)/(3)Am^ - 1

JEE Main

Exam: JEE Main
Subject: Physics
Chapter: Magnetic Properties of Matter

JEE Main · Physics · Magnetic Properties of Matter

A paramagnetic material shows a net magnetization of 8 A m ^ -1...

A paramagnetic material shows a net magnetization of ${8 A m}^{-1}$ when placed in an external magnetic field of intensity $\text{0}\text{.6 T}$ at a temperature of $\text{4}\text{K}$ . When the same material is placed in an external magnetic field of intensity $\text{0}\text{.2 T}$ at a temperature of $\text{16 K}$ , the magnetization will be

Options

A $\dfrac{32}{3}Am^{- 1}$
B $\dfrac{2}{3}Am^{- 1}$
C $6Am^{- 1}$
D $2.4Am^{- 1}$

Correct answer

B. $\dfrac{2}{3}Am^{- 1}$

Step-by-step solution

According to Curie's law,

Magnetization, $I ∝ \dfrac{MagneticInduction ( B )}{Absolutetemperature ( T )}$

$⇒ \dfrac{I2}{I1} = \dfrac{{B}_{2}{T}_{1}}{{B}_{1}{T}_{2}}$

$⇒ \dfrac{I2}{8} = \dfrac{0 . 2 \times 4}{0 . 6 \times 16}$

$⇒ {I}_{2} = \dfrac{2}{3}Am^{- 1}$

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