JEE Main
- Exam
- JEE Main
- Subject
- Physics
- Chapter
- Magnetic Properties of Matter
JEE Main · Physics · Magnetic Properties of Matter
A bar magnet of magnetic moment M is placed at a distance D with...
A bar magnet of magnetic moment is placed at a distance with its axis along positive -axis. Likewise, second bar magnet of magnetic moment is placed at a distance on positive -axis and perpendicular to it as shown in the figure. The magnitude of magnetic field at the origin is \left|\overset{→}{B}\right| = \alpha\left[\dfrac{\mu0}{4\pi}\dfrac{M}{D3}\right]\alphaD > >l
Options
- A
- B
- C
- D
Correct answer
B.
Step-by-step solution
since~
{B}_{net} = {B}_{axis} - {B}_{equator} = \dfrac{{μ}_{0}M}{4\piD^{3}} \left(2 - \dfrac{1}{8}\right)</p><p>∴ {B}_{net} = ⇒ \alpha = \dfrac{15}{8}