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Two bar magnets ' P ' and ' Q ' are kept in uniform magnetic field 'B' with magnetic moments ' M _ P ' and ' M _ Q ' respectively. Magnet ' P ' is oscillating with frequency twice that of magnet ' Q '. If the moment of inertia of the magnet ' P ' is twice that of magnet ' Q ' then

Options

  1. AM _ Q =2 MP _ P
  2. BM _ P =2 M _ Q
  3. CM _ P =8 M _ Q
  4. DM _ Q =8 M _ P

Correct answer

C. M _ P =8 M _ Q

Step-by-step solution

The frequency of oscillation given by aligned & f _ p = 1 2 M _ p B I _P and f _ Q = 1 2 M _ Q B I _ Q & f _ p =2 f _ Q & 1 2 M _ P B I _ P =2 1 2 M _ Q B I _ Q & M _ P I _ P =4 M _ Q I _ Q & M _ P M _ Q =4 I _ P I _ Q =8 [ I _ P =2 I _ Q ] aligned

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