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JEE Main
Exam
JEE Main
Subject
Physics
Chapter
Magnetic Properties of Matter

JEE Main · Physics · Magnetic Properties of Matter

There are 2.0 × 10 ^ 24 molecular dipoles in a paramagnetic salt....

There are 2.0×10242.0 \times {10}^{24} molecular dipoles in a paramagnetic salt. Each has dipole moment 1.5×10−23Am21.5 \times {10}^{- 23}Am^{2} . Find maximum (saturation) magnetization in the specimen.

Options

  1. A20Am220Am^{2}
  2. B30Am230Am^{2}
  3. C200Am2200Am^{2}
  4. D50Am250Am^{2}

Correct answer

B. 30Am230Am^{2}

Step-by-step solution

Maximum magnetization

M=μ×no.ofatomsunitvolumeM = \mu \times \dfrac{no . ofatoms}{unitvolume}

=1.5×10−23Am2×2×1024= 1.5 \times {10}^{- 23}Am^{2} \times 2 \times {10}^{24}

=30Am2= 30Am^{2}
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