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Two short bar magnets have their magnetic moments 1.2 Am ^2 and 1.0 Am ^2 . They are placed on a horizontal table parallel to each other at a distance of 20 ~cm between their centres, such that their north poles pointing towards geographic south. They have common magnetic equatorial line. Horizontal component of earth's field is 3.6 10⁻⁵ ~T . Then, the resultant horizontal magnetic induction at mid point of the line

Options

  1. A3.6 10⁻⁵ ~T
  2. B1.84 10⁻⁴ ~T
  3. C2.56 10⁻⁴ ~T
  4. D5.8 10⁻⁵ ~T

Correct answer

C. 2.56 10⁻⁴ ~T

Step-by-step solution

We knows, B= ₀ 4 M r^3 Hence the resultant horizontal magnetic induction point of the line joining their conters is aligned B & =B₁+B₂+B_H & = 10⁻⁷ 1.2 (10 10⁻² )^3 + 10⁻⁷ 1 (10 10⁻² )^3 +3.6 10⁻⁵ & =1.2 10⁻⁴+1 10⁻⁴+0.36 10⁻⁴ & =2.56 10⁻⁴ ~T aligned

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