99 Percentile Qs Bank for JEE MainPhysicsNuclear Physics
Consider the nuclear reaction X 200 → A 110 + B 80 + 10 n 1 . If the binding energy per nucleon for X , A and B are 7 . 4 MeV , 8 . 2 MeV and 8 . 1 MeV respectively, then the energy released in the reaction -
Options
- A70 MeV
- B200 MeV
- C190 MeV
- D10 MeV
Correct answer
A. 70 MeV
Step-by-step solution
For X: energy E 1 = 200 × 7.4 = 1480 M e V For A: energy E 2 = 110 × 8.2 = 902 M e V For B: energy E 3 = 80 × 8.1 = 648 M e V Energy Released E = E 1 + E 2 + E 3 E = 902 + 648 - 1480 = 70 M e V