99 Percentile Qs Bank for JEE MainPhysicsNuclear Physics
If the binding energy of N 14 is 7 . 5   MeV per nucleon and that of N 15 is 7 . 7   MeV per nucleon. then the energy required to remove a neutron from N 15 is
Options
- A5 . 25   MeV
- B0 . 2   MeV
- C10 . 5   MeV
- D0 . 4   MeV
Correct answer
C. 10 . 5   MeV
Step-by-step solution
The total binding energy, N 14 = 7 . 5 × 14   MeV N 15 = 7 . 7 × 15   MeV The energy required to remove a neutron from N 15 , E = BE   N 15 - BE   N 14 E = 7 . 7 × 15 - 7 . 5 × 14   MeV ⇒     E = 10 . 5   MeV