99 Percentile Qs Bank for JEE MainPhysicsNuclear Physics
Assume that a neutron breaks into a proton and electron. The energy released during this process is (Mass of neutron = 1.6725 × 10 - 27   K g = m a s s   o f   p r o t o n = 1.6725 × 10 - 27   k g , mass of electron = 9 × 10 - 31   K g ) ,
Options
- A0.73 MeV
- B7.10 MeV
- C6.30 MeV
- D5.4 MeV
Correct answer
A. 0.73 MeV
Step-by-step solution
∆ m = m p + m e - m n Energy released = ∆ m × c 2