If 200 MeV of energy is released in the fission of one nucleus of ₉₂²³⁶ U , the number of nuclei that must undergo fission to release an energy of 1000 ~J is

Step-by-step solution

Energy released in the fission of one nucleus aligned & =200 MeV & =200 1.6 10⁻¹³ ~J & =3.2 10⁻¹¹ ~J aligned Energy to be released =1000 ~J 3.2 10⁻¹¹ ~J energy is released due to number of nucleus fissioned =1 1000 ~J energy is released due to number of nucleus fissioned aligned & = 1 1000 3.2 10⁻¹¹ & =3.125 10¹³ nucleus aligned