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99 Percentile Qs Bank for JEE MainPhysicsNuclear Physics

If 200 MeV of energy is released in the fission of one nucleus of ₉₂²³⁵ U , then the number of nuclei that must undergo fission to release an energy of 1000 ~J is

Options

  1. A3.125 10¹³
  2. B6.25 10¹³
  3. C12.5 10¹³
  4. D3.125 10¹⁴

Correct answer

A. 3.125 10¹³

Step-by-step solution

array rlrl Number of nuclei & = E_ total E₁ = 1000 ~J 200 MeV & = 1000 ~J 200 10^6 1.6 10⁻¹⁹ ~J & N & = 10¹⁴ 3.2 & N & =3.125 10¹³ array

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