99 Percentile Qs Bank for JEE MainPhysicsSemiconductors
The figure gives a system of logic gates. From the study of the truth table, it can be found that to produce a high output ( 1 ) at R , we must have
Options
- AX = 0 , Y = 1
- BX = 1 , Y = 1
- CX = 1 , Y = 0
- DX = 0 , Y = 0
Correct answer
C. X = 1 , Y = 0
Step-by-step solution
From figure X ¯ + Y + X Y ¯ ¯ = R R = X ¯ + Y ¯ ⋅ X Y ¯ ¯ R = X ¯ Y ¯ X ¯ + Y ¯ R = X Y ¯ X ¯ + Y R = X X ¯ Y ¯ + X Y ¯ R = X Y ¯ i.e., when X = 1 Y = 0 ⇒ R = 1