In a p -type semiconductor, the acceptor level is situated 57   meV above the valence band. The maximum wavelength of light required to produce a hole will be

Step-by-step solution

Given that the level of energy of the acceptor band is above the valence band by, E = 57   meV The energy of the photon having just enough energy to overcome the gap is given by, E = hc λ ⇒ λ = hc E Speed of light c = 3 × 10 8   m s Planck's constant h = 6 . 63 × 10 - 34   Js , Substituting values, λ = 6 . 6 × 10 - 34 × 3 × 10 8 57 × 10 - 3 × 1 . 6 × 10 - 19 λ = 21700 A ∘ The maximum wavelength of light required to produce a