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A Zener diode voltage regulator operated in the range 120 ~V -180 ~V produces a constant supply of 110 ~V and 250 ~mA to the load. If the maximum current is equally shared between the load and the Zener diode, then the values of load resistance (R_L ) and series resistance (R_S ) are respectively

Options

  1. AR_L=280 , R_S=70
  2. BR_L=440 , R_S=140
  3. CR_L=70 , R_S=280
  4. DR_L=440 , R_S=1400

Correct answer

B. R_L=440 , R_S=140

Step-by-step solution

We have, R_L= V_L I_L = 110 250 10⁻³ =440 As current is equally shared by Zener diode and resistance R . So, I_Z=250 ~mA Then, I=2 250=500 ~mA [ I=I_L+I_Z ]=0.5 ~mA So, R_S= V_S I = (180-110) 0.5 = 70 0.5 =140 [ when current is maximum V=180 ~V ]

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