99 Percentile Qs Bank for JEE MainPhysicsUnits and Dimensions
The volume of a liquid is proportional to......, given its density , viscosity and t the time of flow through a capillary tube of length L and radius R , with a pressure difference p across its ends
Options
- Ap^2 R^2 t L
- Bp R^4 L t
- Cp R^4 t L
- Dp^2 R^2 t L^2
Correct answer
C. p R^4 t L
Step-by-step solution
Given, density of liquid = Viscosity = Time of flow =t , Length of tube =L Radius of cross-section =R Pressure difference between end s=p According to Poiseuille's formula, the rate of flow of liquid through a horizontal tube = Volume of liquid flow Time taken i.e. Q= V t = 8 p R^4 L V= 8 p R^4 L t , (where 8 is a constant.) Hence, V p R^4 t L So, the option (c) is correct, where volume of flow of liquid is proportional to p R^4 t L .