A motor of power P₀ is used to deliver water at a certain rate through a given horizontal pipe. To increase the rate of flow of water through the same pipe n times, the power of the motor is increased to P₁ . The ratio of P₁ to P₀ is

Step-by-step solution

Power of motor initially =P₀ Let, rate of flow of motor =(x) Since, power, aligned P₀ & = work time = m g y t & =m g ( y t ), y t & =x= rate of flow of water aligned If rate of flow of water is increased by n times, i e , (nx). Increased power aligned P₁ & = m g y^ t & =m g ( y^ t )=m g n x aligned The ratio of power gathered P₁ P₀ = n m g x m g x P₁ P₀ = n 1 P₁: P₀=n: 1 gathered