99 Percentile Qs Bank for JEE MainPhysicsWork, Power and Energy
A car of mass 1000 ~kg having a velocity of 10 ~ms ⁻¹ collides a horizontally mounted spring. If the spring constant is 4000 Nm ⁻¹ , then the maximum compression of the spring is
Options
- A25 ~m
- B15 ~m
- C5 ~m
- D10 ~m
Correct answer
C. 5 ~m
Step-by-step solution
Mass of car, m=1000 ~kg Velocity, v=10 ~m / s Spring constant, k =4000 Nm ⁻¹ Apply the conservation of energy 1 2 m v^2= 1 2 k( x)^2 x = mv ^2 k = 1000 100 4000 Compression of the spring x=5 ~m