A solid spherical ball is rolled up an inclined plane of angle of inclination 30^ with an initial speed of 4 ~m / s at the bottom of the inclination. How far will the ball go up the plane. ( . Use .g=10 ~m / s ^2 )

Step-by-step solution

aligned & As P.E E _ i +( K . E )_ i =( P . E )_ f +( K . E )_ f & 0+ 1 2 m 4^2+ 1 2 ( 2 5 mR ^2 ) 4^2 R ^2 = mgh & 4^2 2 + 1 5 4^2=10 ~h 8+3.2=10 ~h & 1.12= h h =1.12 ~m & So, = h 30^ = h 1 / 2 =2 ~h =2.24 ~m =224 ~cm aligned