A ball of mass 2 ~g released from the top of an inclined plane describes a circular motion of radius 20 ~cm in the vertical plane upon reaching the bottom. The minimum height of the inclined plane is

Step-by-step solution

The motion of ball is as shown below At bottom of incline (at P ) the potential energy of ball is converted into kinetic energy i.e., aligned & 1 2 m v^2=m g h & v= 2 g h & aligned To complete the vertical circle, the velocity of ball should be at least 5 g R . aligned v & 5 g R 2 g h & 5 g R aligned [From Eq. (i)] h 5 2 R or h_ = 5 2 20=50 ~cm