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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Photometry

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Photometry

A source emits light of wavelengths 555 nm and 600 nm . The radiant...

A source emits light of wavelengths 555 nm555 \text{ nm} and 600 nm600 \text{ nm}. The radiant flux of the 555 nm555 \text{ nm} part is 40 W40 \text{ W} while that of the 600 nm600 \text{ nm} part is 30 W30 \text{ W}. The relative luminosity at 600 nm600 \text{ nm} is 0.60.6. Determine the total radiant flux.

Options

  1. A10 W10 \text{ W}
  2. B80 W80 \text{ W}
  3. C70 W70 \text{ W}
  4. D58 W58 \text{ W}

Correct answer

C. 70 W70 \text{ W}

Step-by-step solution

The total radiant flux is defined as the total power of electromagnetic radiation emitted by the source. It is simply the sum of the radiant fluxes of all the individual wavelength components.

Given:
Radiant flux of the 555 nm555 \text{ nm} part =40 W= 40 \text{ W}
Radiant flux of the 600 nm600 \text{ nm} part =30 W= 30 \text{ W}

Total radiant flux =40 W+30 W=70 W= 40 \text{ W} + 30 \text{ W} = 70 \text{ W}

The relative luminosity is required only for calculating the luminous flux and is not used in finding the total radiant flux.
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