Concepts Of Physics MCQ Edition [Volume 1]PhysicsPhotometry
A source emits light of wavelengths 555 nm and 600 nm . The radiant flux of the 555 nm part is 40 W while that of the 600 nm part is 30 W . The relative luminosity at 600 nm is 0.6 . Determine the total radiant flux.
Options
- A10 W
- B80 W
- C70 W
- D58 W
Correct answer
C. 70 W
Step-by-step solution
The total radiant flux is defined as the total power of electromagnetic radiation emitted by the source. It is simply the sum of the radiant fluxes of all the individual wavelength components. Given: Radiant flux of the 555 nm part = 40 W Radiant flux of the 600 nm part = 30 W Total radiant flux = 40 W + 30 W = 70 W The relative luminosity is required only for calculating the luminous flux and is not used in finding the total radiant flux.