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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Rotational Mechanics

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Rotational Mechanics

A disc rotates about its axis with a uniform angular acceleration...

A disc rotates about its axis with a uniform angular acceleration of 4 rad/s24 \text{ rad/s}^2. Determine the radial and tangential accelerations of a particle located 1 cm1 \text{ cm} from the axis at the end of the first second after the disc begins rotating.

Options

  1. A16 cm/s216 \text{ cm/s}^2, 4 cm/s24 \text{ cm/s}^2
  2. B4 cm/s24 \text{ cm/s}^2, 16 cm/s216 \text{ cm/s}^2
  3. C4 cm/s24 \text{ cm/s}^2, 4 cm/s24 \text{ cm/s}^2
  4. D8 cm/s28 \text{ cm/s}^2, 4 cm/s24 \text{ cm/s}^2

Correct answer

A. 16 cm/s216 \text{ cm/s}^2, 4 cm/s24 \text{ cm/s}^2

Step-by-step solution

Given initial angular velocity ω0=0\omega_0 = 0 and angular acceleration α=4 rad/s2\alpha = 4 \text{ rad/s}^2.

The angular velocity at time t=1 st = 1 \text{ s} is given by:

ω=ω0+αt=0+4×1=4 rad/s\omega = \omega_0 + \alpha t = 0 + 4 \times 1 = 4 \text{ rad/s}

The radial acceleration ara_r of a particle at a distance r=1 cmr = 1 \text{ cm} from the axis is:

ar=ω2r=(4)2×1=16 cm/s2a_r = \omega^2 r = (4)^2 \times 1 = 16 \text{ cm/s}^2

The tangential acceleration ata_t of the particle is:

at=αr=4×1=4 cm/s2a_t = \alpha r = 4 \times 1 = 4 \text{ cm/s}^2
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