A steel tube of length 1.00 m is struck at one end. A person with an ear close to the opposite end hears the sound of the blow twice: once travelling through the body of the tube and once through the air inside the

Question

Quantrex Academy · Accepted Answer

Correct answer: B. 2.75 ms

Time taken by sound to travel through air is

t_1 = \dfrac{L}{v_a} = \dfrac{1}{340} \text{ s}

Time taken by sound to travel through steel is

t_2 = \dfrac{L}{v_s} = \dfrac{1}{5200} \text{ s}

The time gap between the two hearings is

\Delta t = t_1 - t_2

\Delta t = \dfrac{1}{340} - \dfrac{1}{5200}

\Delta t = \dfrac{5200 - 340}{340 \times 5200}

\Delta t = \dfrac{4860}{1768000} \text{ s}

\Delta t \approx 2.75 \times 10^{-3} \text{ s} = 2.75 \text{ ms}

A steel tube of length 1.00 m is struck at one end. A person with...

Options

Correct answer

Step-by-step solution

More from Sound Waves