Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
Concepts Of Physics MCQ Edition [Volume 1]PhysicsSound Waves

A steel tube of length 1.00 m is struck at one end. A person with an ear close to the opposite end hears the sound of the blow twice: once travelling through the body of the tube and once through the air inside the tube. Determine the time gap between the two hearings. (Take the speed of sound in air as 340 m/s and in steel as 5200 m/s .)

Options

  1. A3.13 ms
  2. B2.75 ms
  3. C2.84 ms
  4. D2.94 ms

Correct answer

B. 2.75 ms

Step-by-step solution

Time taken by sound to travel through air is t₁ = L v_a = 1 340 s Time taken by sound to travel through steel is t₂ = L v_s = 1 5200 s The time gap between the two hearings is t = t₁ - t₂ t = 1 340 - 1 5200 t = 5200 - 340 340 5200 t = 4860 1768000 s t 2.75 10⁻³ s = 2.75 ms

Practice Sound Waves on Quantrex Academy →

More from Sound Waves

A man stands in front of a large wall at a distance of 50.0 m and claps his hands at regular intervals. Initially, the interval is large. He progressively reduces the interval, fixDetermine the minimum and maximum wavelengths of sound in water within the audible range ( 20 – 20000 Hz ) for an average human ear. The speed of sound in water is 1450 m s ⁻¹ .A person is able to hear sound waves within the frequency range of 20 Hz to 20 kHz . Determine the minimum and maximum wavelengths of sound audible to the person. Assume the speed Sound is primarily transmitted in the forward direction when its wavelength is significantly smaller than the speaker's diameter. Determine the frequency at which the sound's wavelSound waves from a loudspeaker propagate nearly uniformly in all directions when the sound's wavelength is significantly greater than the loudspeaker's diameter. Compute the frequeDuring a spiritual gathering, the devotees chant HARE-RAM HARE-RAM. The sound is amplified by a loudspeaker and returns after reflecting from a building situated 80 m away from theA travelling sound wave is described by the equation y = 6.0 (600 t - 1.8 x) , with y measured in 10⁻⁵ m , t in second, and x in metre. Determine the ratio of the displacement amplA travelling sound wave is described by the equation y = 6.0 (600 t - 1.8 x) , with y measured in 10⁻⁵ m , t in second, and x in metre. Determine the ratio of the velocity amplitud Full Sound Waves list All Concepts Of Physics MCQ Edition [Volume 1] PYQs