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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Speed of Light

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Speed of Light

In a Michelson experiment intended for measuring the speed of...

In a Michelson experiment intended for measuring the speed of light, the total distance travelled by light between two successive reflections from the rotating mirror is 4.8 km4.8 \text{ km}. The rotating mirror is shaped as a regular octagon. Find the minimum non-zero angular speed of the mirror required for the image to be formed at the exact position where a stationary mirror would form it.

Options

  1. A3906.25 rev/s3906.25 \text{ rev/s}
  2. B31250 rev/s31250 \text{ rev/s}
  3. C15625 rev/s15625 \text{ rev/s}
  4. D7812.5 rev/s7812.5 \text{ rev/s}

Correct answer

D. 7812.5 rev/s7812.5 \text{ rev/s}

Step-by-step solution

The time taken by light to travel the given distance DD is

t=Dc=4.8×1033×108=1.6×10−5 st = \dfrac{D}{c} = \dfrac{4.8 \times 10^3}{3 \times 10^8} = 1.6 \times 10^{-5} \text{ s}

For the image to be formed at the exact position as a stationary mirror, the regular octagonal mirror must rotate by an angle equal to the angle between its adjacent faces in time tt.

The angle between adjacent faces of a regular octagon is 18\dfrac{1}{8} of a revolution.

The minimum non-zero angular speed ff in revolutions per second is given by

f=1/8tf = \dfrac{1/8}{t}

f=18×1.6×10−5f = \dfrac{1}{8 \times 1.6 \times 10^{-5}}

f=10512.8=7812.5 rev/sf = \dfrac{10^5}{12.8} = 7812.5 \text{ rev/s}
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