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Concepts Of Physics MCQ Edition [Volume 1]
Exam
Concepts Of Physics MCQ Edition [Volume 1]
Subject
Physics
Chapter
Photometry

Concepts Of Physics MCQ Edition [Volume 1] · Physics · Photometry

A point source of light travels in a straight line parallel to a...

A point source of light travels in a straight line parallel to a plane table. Consider a small portion of the table directly beneath the line of motion of the source. The illuminance at this portion varies with its distance rr from the source as

Options

  1. AI∝1r4I \propto \dfrac{1}{r^4}
  2. BI∝1r2I \propto \dfrac{1}{r^2}
  3. CI∝1r3I \propto \dfrac{1}{r^3}
  4. DI∝1rI \propto \dfrac{1}{r}

Correct answer

C. I∝1r3I \propto \dfrac{1}{r^3}

Step-by-step solution

Let hh be the constant height of the point source above the plane table.

The illuminance EE at a small portion of the table is given by E=I0cos⁡θr2E = \dfrac{I_0 \cos \theta}{r^2}, where I0I_0 is the luminous intensity of the source, rr is the distance between the source and the portion, and θ\theta is the angle of incidence.

Since the small portion is directly beneath the line of motion of the source, the vertical distance from the source to the table is hh.

From the geometry of the setup, the angle of incidence θ\theta satisfies cos⁡θ=hr\cos \theta = \dfrac{h}{r}.

Substituting this into the formula for illuminance, we get:

E=I0r2(hr)=I0hr3E = \dfrac{I_0}{r^2} \left(\dfrac{h}{r}\right) = \dfrac{I_0 h}{r^3}

Since I0I_0 and hh are constants, the illuminance varies with the distance rr as E∝1r3E \propto \dfrac{1}{r^3}.
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