A household supply of electricity operates at 220 V (rms value) and 50 Hz . Determine the peak voltage and the minimum possible time in which the voltage can change from its rms value to zero.

Step-by-step solution

Given V_ rms = 220 V and f = 50 Hz . The peak voltage V₀ is given by: V₀ = 2 V_ rms = 2 220 311 V The instantaneous voltage is V = V₀ ( t) . The minimum time required for the voltage to change from its rms value to zero is the same as the time taken to change from zero to its rms value. When the voltage is zero, t₁ = 0 . When the voltage reaches its rms value, V = V₀ 2 . V₀ 2 = V₀ ( t₂) ( t₂) = 1 2 t₂ = 4 The phase difference is = 4 . The time taken t is: t = = /4 2 f = 1 8f Substituting f = 50 Hz : t = 1 8 50 = 1