When connected to an AC source, a resistive coil consumes a peak power of 80 W . Determine the energy consumed by the coil over a duration of 100 seconds , given that this time is significantly greater than the time period of the source.

Step-by-step solution

For a resistive coil connected to an AC source, the instantaneous power is given by P(t) = P₀ ^2( t) , where P₀ is the peak power. Given the peak power P₀ = 80 W . The average power consumed over a duration significantly greater than the time period is: P_ avg = P₀ 2 = 80 2 = 40 W The energy consumed by the coil over a duration of t = 100 s is: E = P_ avg t E = 40 100 = 4000 J