A coil with an inductance of 5.0 mH and negligible resistance is connected to an oscillator that provides an output voltage E = 10 V t . Determine the peak currents in the circuit for = 100 s ⁻¹ , 500 s ⁻¹ , and 1000 s ⁻¹ .

Step-by-step solution

The peak current in an inductive circuit is given by I₀ = V₀ X_L , where X_L = L is the inductive reactance. Given V₀ = 10 V and L = 5.0 mH = 5.0 10⁻³ H . For = 100 s ⁻¹ : X_L = 100 5.0 10⁻³ = 0.5 I₀ = 10 0.5 = 20 A For = 500 s ⁻¹ : X_L = 500 5.0 10⁻³ = 2.5 I₀ = 10 2.5 = 4.0 A For = 1000 s ⁻¹ : X_L = 1000 5.0 10⁻³ = 5.0 I₀ = 10 5.0 = 2.0 A The peak currents are 20 A , 4.0 A , and 2.0 A .