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Concepts Of Physics MCQ Edition [Volume 2]PhysicsCalorimetry

A mass of 1 kg of ice at 0^ C is mixed with 1 kg of steam at 100^ C . Determine the composition of the system once thermal equilibrium is established. The latent heat of fusion of ice is 3.36 10^5 J kg ⁻¹ and the latent heat of vaporization of water is 2.26 10^6 J kg ⁻¹ .

Options

  1. A335 g steam and 1.665 kg water
  2. B851 g steam and 1.149 kg water
  3. C1.335 kg steam and 665 g water
  4. D665 g steam and 1.335 kg water

Correct answer

D. 665 g steam and 1.335 kg water

Step-by-step solution

Heat required to convert 1 kg of ice at 0^ C to water at 100^ C is given by: Q₁ = m_ ice L_f + m_ ice C_w T Q₁ = 1 3.36 10^5 + 1 4200 100 Q₁ = 3.36 10^5 + 4.20 10^5 = 7.56 10^5 J Heat released if the entire 1 kg of steam at 100^ C condenses to water at 100^ C : Q₂ = m_ steam L_v = 1 2.26 10^6 = 22.6 10^5 J Since Q₂ > Q₁ , the available heat from steam is more than sufficient to melt the ice and raise its temperature to 100^ C . Thus, the final temperature of the mixture will be 100^ C and only a fraction of the ste

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