Determine the electric field within a copper wire that has a cross-sectional area of 2.0 mm ^2 and carries a current of 1 A . The resistivity of copper is 1.7 10⁻⁸ m .

Step-by-step solution

Given, cross-sectional area A = 2.0 mm ^2 = 2.0 10⁻⁶ m ^2 Current I = 1 A Resistivity = 1.7 10⁻⁸ m Using the relation between electric field, resistivity, and current density: E = J Since J = I A , we have: E = ( I A ) Substituting the given values: E = 1.7 10⁻⁸ 1 2.0 10⁻⁶ E = 0.85 10⁻² V/m E = 0.0085 V/m