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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Electric Current in Conductors

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Electric Current in Conductors

An ammeter and a voltmeter are used to measure the current in a...

An ammeter and a voltmeter are used to measure the current in a conductor and the potential difference across its terminals. Both meters draw negligible currents. The ammeter is perfectly accurate, whereas the voltmeter possesses a zero error (meaning it fails to read zero when no potential difference is present). Determine the zero error if the readings under two distinct conditions are 1.75 A1.75 \text{ A}, 14.4 V14.4 \text{ V} and 2.75 A2.75 \text{ A}, 22.4 V22.4 \text{ V}.

Options

  1. A0.4 V0.4 \text{ V}
  2. B8.0 V8.0 \text{ V}
  3. C0.2 V0.2 \text{ V}
  4. D0.8 V0.8 \text{ V}

Correct answer

A. 0.4 V0.4 \text{ V}

Step-by-step solution

Let RR be the resistance of the conductor and ee be the zero error of the voltmeter.

The true potential difference across the conductor is given by Ohm's law as V=IRV = IR.

The voltmeter reading is V′=V+e=IR+eV' = V + e = IR + e.

Using the given readings, we can write two equations:

14.4=1.75R+e14.4 = 1.75 R + e

22.4=2.75R+e22.4 = 2.75 R + e

Subtracting the first equation from the second yields:

22.4−14.4=(2.75−1.75)R22.4 - 14.4 = (2.75 - 1.75) R

8.0=1.0R⇒R=8.0Ω8.0 = 1.0 R \Rightarrow R = 8.0 \Omega

Substituting the value of RR into the first equation:

14.4=1.75×8.0+e14.4 = 1.75 \times 8.0 + e

14.4=14.0+e14.4 = 14.0 + e

e=0.4 Ve = 0.4 \text{ V}
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