When connected across an external resistor, the potential difference between the terminals of a battery having an emf of 6.0 V and an internal resistance of 1 drops to 5.8 V . Determine the resistance of the external resistor.

Step-by-step solution

Given E = 6.0 V , r = 1 , and V = 5.8 V . The terminal potential difference of the battery is given by V = E - Ir . Substituting the given values: 5.8 = 6.0 - I(1) I = 0.2 A Using Ohm's law for the external resistor, V = IR . 5.8 = 0.2 R R = 5.8 0.2 = 29