For the circuit shown in the figure, determine the current through the 10 resistor when the switch S is open.

Correct answer: D. 0.1 A When the switch S is open, the 10 and 20 resistors are in series. Equivalent resistance of the circuit, R_ eq = 10 + 20 = 30 . Current through the circuit, I = V R_ eq = (3)/(30) = 0.1 A . Since the resistors are in series, the current through the 10 resistor is 0.1 A .

Concepts Of Physics MCQ Edition [Volume 2]

Exam: Concepts Of Physics MCQ Edition [Volume 2]
Subject: Physics
Chapter: Electric Current in Conductors

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Electric Current in Conductors

For the circuit shown in the figure, determine the current through...

For the circuit shown in the figure, determine the current through the

10 \text{ } \Omega

resistor when the switch

S

is open.

Options

A $0.15 \text{ A}$
B $0.05 \text{ A}$
C $0.3 \text{ A}$
D $0.1 \text{ A}$

Correct answer

D. $0.1 \text{ A}$

Step-by-step solution

When the switch

S

is open, the

10 \text{ } \Omega

and

20 \text{ } \Omega

resistors are in series.

Equivalent resistance of the circuit,

R_{eq} = 10 + 20 = 30 \text{ } \Omega

.

Current through the circuit,

I = \dfrac{V}{R_{eq}} = \dfrac{3}{30} = 0.1 \text{ A}

.

Since the resistors are in series, the current through the

10 \text{ } \Omega

resistor is

0.1 \text{ A}

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