Determine the current in the three resistors depicted in the figure.

Step-by-step solution

Let the potential of the bottom-left node be 0 V . Since the top-left node is connected to the bottom-left node by an ideal connecting wire, its potential is also 0 V . Moving along the top branch from left to right, the potential decreases by 2 V across each battery because the positive terminal (longer line) is on the left. Potential at the top of the first resistor = 0 - 2 = -2 V . Potential at the top of the second resistor = -2 - 2 = -4 V . Potential at the top of the third resistor = -4 - 2 = -6 V . Similarly