The electromotive force E and the internal resistance r of a battery are 4.3 V and 1.0 respectively. The external resistance R is 50 . The resistances of the ammeter and voltmeter are 2.0 and 200 respectively. The switch is thrown to the other side such that the voltmeter is now connected across the series combination of R and the ammeter. What will be the readings of the two meters now?

Step-by-step solution

When the switch is thrown to the other side, the voltmeter is connected in parallel with the series combination of the resistor R and the ammeter. Resistance of the series combination of R and the ammeter: R_s = R + R_A = 50 + 2.0 = 52 Equivalent resistance of the parallel combination of the voltmeter and R_s : R_p = R_s R_V R_s + R_V = 52 200 52 + 200 = 10400 252 = 2600 63 Total equivalent resistance of the circuit including the internal resistance of the battery: R_ eq = R_p + r = 2600 63 + 1.0 = 2663 63 Total cu