Determine the charge on the capacitor depicted in the accompanying figure.

Step-by-step solution

In steady state, the capacitor acts as an open circuit. The current flows only through the series combination of the resistors. The equivalent resistance of the circuit is: R_ eq = 10 + 20 = 30 The current in the circuit is: I = V R_ eq = 2 30 = 1 15 A The voltage across the capacitor is equal to the potential difference across the 10 resistor: V_C = I 10 = 1 15 10 = 2 3 V The charge on the capacitor is: Q = C V_C = 6 F 2 3 V = 4 C