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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Electric Current through Gases

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Electric Current through Gases

When the plate voltage is 36 V , the power delivered in the plate...

When the plate voltage is 36 V36 \text{ V}, the power delivered in the plate circuit of a diode is 1.0 W1.0 \text{ W}. Determine the power delivered if the plate voltage is raised to 49 V49 \text{ V}. Assume the Langmuir–Child equation holds true.

Options

  1. A1.9 W1.9 \text{ W}
  2. B2.2 W2.2 \text{ W}
  3. C1.4 W1.4 \text{ W}
  4. D1.6 W1.6 \text{ W}

Correct answer

B. 2.2 W2.2 \text{ W}

Step-by-step solution

According to the Langmuir-Child equation, the plate current IpI_p is proportional to Vp3/2V_p^{3/2}.

Ip=kVp3/2I_p = k V_p^{3/2}

The power delivered in the plate circuit is given by:

P=VpIp=kVp5/2P = V_p I_p = k V_p^{5/2}

Given P1=1.0 WP_1 = 1.0 \text{ W} at Vp1=36 VV_{p1} = 36 \text{ V} and Vp2=49 VV_{p2} = 49 \text{ V}.

P2P1=(Vp2Vp1)5/2\dfrac{P_2}{P_1} = \left(\dfrac{V_{p2}}{V_{p1}}\right)^{5/2}

P2=1.0×(4936)5/2P_2 = 1.0 \times \left(\dfrac{49}{36}\right)^{5/2}

P2=((76)2)5/2=(76)5P_2 = \left(\left(\dfrac{7}{6}\right)^2\right)^{5/2} = \left(\dfrac{7}{6}\right)^5

P2=168077776≈2.16 WP_2 = \dfrac{16807}{7776} \approx 2.16 \text{ W}

Rounding to one decimal place, P2≈2.2 WP_2 \approx 2.2 \text{ W}.
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