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Concepts Of Physics MCQ Edition [Volume 2]PhysicsKinetic Theory of Gases

A gas cylinder features walls capable of withstanding a maximum pressure of 1.0 10^6 Pa . Inside, it holds a gas at 8.0 10^5 Pa and 300 K . The cylinder is heated steadily. Assuming no change in volume, determine the temperature at which the cylinder will break.

Options

  1. A325 K
  2. B375 K
  3. C240 K
  4. D450 K

Correct answer

B. 375 K

Step-by-step solution

Given initial pressure P₁ = 8.0 10^5 Pa and initial temperature T₁ = 300 K . The maximum pressure the cylinder can withstand is P₂ = 1.0 10^6 Pa . Since the volume of the cylinder remains constant, Gay-Lussac's law is applicable: P₁ T₁ = P₂ T₂ Substituting the given values: 8.0 10^5 300 = 1.0 10^6 T₂ T₂ = 1.0 10^6 300 8.0 10^5 T₂ = 10 8 300 T₂ = 375 K

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