Determine the molecular weight of an ideal gas if its density at STP is 1.25 10⁻³ g cm ⁻³ .

Step-by-step solution

Given density of the ideal gas, d = 1.25 10⁻³ g cm ⁻³ = 1.25 g L ⁻¹ . At standard temperature and pressure (STP), the molar volume of an ideal gas is V_m = 22.4 L mol ⁻¹ . The molecular weight M of the gas can be calculated using the relation: M = d V_m Substituting the given values: M = 1.25 g L ⁻¹ 22.4 L mol ⁻¹ = 28.0 g mol ⁻¹