Equal masses of air are sealed inside two vessels having volumes V₀ and 2V₀ . When the first vessel is maintained at a temperature of 300 K and the second at 600 K , what is the ratio of the pressures in the two vessels?

Step-by-step solution

Using the ideal gas equation, PV = nRT Since equal masses of air are taken, the number of moles n is the same for both vessels. For the first vessel: P₁ V₀ = nR(300) P₁ = 300nR V₀ For the second vessel: P₂ (2V₀) = nR(600) P₂ = 600nR 2V₀ = 300nR V₀ The ratio of pressures is: P₁ P₂ = 300nR V₀ 300nR V₀ = 1 1 Thus, the ratio is 1:1 .