A 10 -cm long portion of a straight wire carrying a 10 A current is situated in a 0.1 T magnetic field that is oriented at an angle of 53^ relative to the wire. What magnetic force acts on this portion of the wire?

Step-by-step solution

The magnetic force on a current-carrying wire is given by the formula: F = I( L B ) The magnitude of the force is: F = I L B Given values are: I = 10 A L = 10 cm = 0.1 m B = 0.1 T = 53^ Substituting these values into the formula: F = 10 0.1 0.1 (53^ ) F = 0.1 4 5 = 0.08 N From the cross product L B , the direction of the magnetic force is perpendicular to both the wire and the magnetic field.