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Concepts Of Physics MCQ Edition [Volume 2]
Exam
Concepts Of Physics MCQ Edition [Volume 2]
Subject
Physics
Chapter
Magnetic Properties of Matter

Concepts Of Physics MCQ Edition [Volume 2] · Physics · Magnetic Properties of Matter

At the centre of a long solenoid carrying a current of 2.0 A , the...

At the centre of a long solenoid carrying a current of 2.0 A2.0 \text{ A}, the magnetic intensity HH is measured to be 1500 A m−11500 \text{ A m}^{-1}. A rod is inserted as the core in the solenoid. Given that the magnetization II of the core is 0.12 A m−10.12 \text{ A m}^{-1}, calculate the susceptibility of the material of the rod.

Options

  1. A1.25×1041.25 \times 10^{4}
  2. B1.8×1021.8 \times 10^{2}
  3. C8.0×10−48.0 \times 10^{-4}
  4. D8.0×10−58.0 \times 10^{-5}

Correct answer

D. 8.0×10−58.0 \times 10^{-5}

Step-by-step solution

The magnetic susceptibility χ\chi of a material is defined as the ratio of the magnetization II to the magnetic intensity HH.

The given values are H=1500 A m−1H = 1500 \text{ A m}^{-1} and I=0.12 A m−1I = 0.12 \text{ A m}^{-1}.

Using the relation for magnetic susceptibility:
χ=IH\chi = \dfrac{I}{H}

Substituting the values:
χ=0.121500\chi = \dfrac{0.12}{1500}

χ=12×10−215×102\chi = \dfrac{12 \times 10^{-2}}{15 \times 10^{2}}

χ=0.8×10−4=8.0×10−5\chi = 0.8 \times 10^{-4} = 8.0 \times 10^{-5}
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