At the centre of a long solenoid carrying a current of 2.0 A , the magnetic intensity H is measured to be 1500 A m ⁻¹ . A rod is inserted as the core in the solenoid. Given that the magnetization I of the core is 0.12 A m ⁻¹ , calculate the susceptibility of the material of the rod.

Step-by-step solution

The magnetic susceptibility of a material is defined as the ratio of the magnetization I to the magnetic intensity H . The given values are H = 1500 A m ⁻¹ and I = 0.12 A m ⁻¹ . Using the relation for magnetic susceptibility: = I H Substituting the values: = 0.12 1500 = 12 10⁻² 15 10² = 0.8 10⁻⁴ = 8.0 10⁻⁵